Question

A car accelerates uniformly from ` 18 km//h` to `36 km//h` in 5 second. Calculate (i) the acceleration and (ii) the distance covered by the car in that time .

Answer 1

Correct Answer - `1 m//s^(2)` ; `37.5m`
Here , `u = 18 km//h = ( 18 xx 1000 m)/( 60 xx 60 s) = 5 m//s, v = 36 km//h = 10 m//s , t = 5 s`
Thus , `a = ( v - u)/( t) = ( 10 - 5)/( 5) = 1 m//s^(2)`
From ` s = ut + (1)/(2) at^(2) , s = 5 xx 5 + (1)/(2) xx 1 xx 5^(2) = 37.5 m`