I toss three coins together
So, total number of outcome `=2^(3)=8`
and possible outcomes are (HHH),(HTT),(THT),(TTH),(HHT),(THH),(HTH),and (TTT)
Now, probability of getting no head=`(1)/(8)`
Hence, the given conclusion is wrong because the probability of no head is `(1)/(8) not (1)/(4)`