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चार गुटके जिनमें सभी के द्रव्यमान m है, भारहीन अवितनय डोरियों द्वारा जुड़े है। इस सम्पूर्ण निकाय को एक चिकने क्षैतिज समतल पर F बल लगाकर खींचा जा रहा है जैसा की चित्र में प्रदर्शित है। डोरियों में उत्पन्न तनाव `T_1,T_2` व् `T_3` की गणना कीजिए। image

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माना बल F सम्पूर्ण निकाय में a त्वरण उत्पन्न करता है, तब
` F-T_1=ma, T_1-T_2 =ma,T_2 -T_3 =ma ` तथा `T_3=ma ` `
(##NTN_HIN_PHY_XI_P1_C07_E03_006_S01.png" width="80%">
अतः त्वरण `a=(F)/(4m) `
अतः `T_1=(3)/(4) F,T_2 =(1)/(2) F,T_3 =(1)/(4) F.`

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