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2 किग्रा के गुटके को एक दीवार के सहारे 50 न्यूटन का क्षैतिज बल लगाकर (संलग्न चित्र के अनुसार रोका गया है । ज्ञात कीजिये -
(i) गुटके पर दीवार की अभिलम्ब प्रतिक्रिया (R ), (ii) गुटके पर घर्षण बल ((f) `(g = 10"मीटर"//"सेकण्ड"^(2))`
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Correct Answer - (i) 50 न्यूटन, (ii) 20 न्यूटन
(i) `R = F = 50` न्यूटन (के विपरीत दिशा में)
(ii) गुटका भार mg के कारण नीचे फिसलने का प्रयास करता है । अतः घर्षण बल (f) ऊपर की ओर लगेगा ।
गुटका स्थिर है `:. F = mg = 2 xx 10 = 20` न्यूटन

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