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एक उपग्रह नियत वेग ` v _ o ` से पृथ्वी के परितः वृत्ताकार कक्षा में घूम रहा है | द्रव्यमान m का एक पिण्ड उपग्रह से बाहर इस प्रकार से फेंका जाता है कि यह पृथ्वी के गुरुत्वाकर्षण खिंचाव से ठीक बाहर पलायन करता है | अलग होते समय पिण्ड की गतिज ऊर्जा है :
A. ` (1)/(2) m v _o ^(2) `
B. ` m v _ o ^(2) `
C. ` (3)/(2) m v _ o ^(2) `
D. ` 2 m v _ o ^(2) `.

1 Answer

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Best answer
Correct Answer - B
पलायन वेग ` v _ e = sqrt2 v_o `
` therefore (1)/(2) mv_e^(2) = (1)/(2) m (sqrt2v_o)^(2) = mv_o^(2)`.
विकल्प (b ) सही है |

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