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m द्रव्यमान के एक कण को एक मशीन द्वारा चलाया जा रहा है। यदि इस मशीन की स्थिर शक्ति k वाट है तथा कण विराम अवस्था से चलना प्रारम्भ करता है तो t समय पर कण पर बल होगा :
A. `sqrt(mk)t^(-1//2)`
B. `sqrt(2mk)t^(-1//2)`
C. `(1)/(2)sqrt(mk)t^(-1//2)`
D. `sqrt((mk)/(2))t^(-1//2)`.

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Correct Answer - D
`(dW)/(dt)=P=k` अथवा `W=kt=(1)/(2)mv^(2)`
`therefore" "v=sqrt((2kt)/(m))`
अतः `" "a=(dv)/(dt)=sqrt((2k)/(m))xx(1)/(2)t^(-1//2)`
कण पर बल, `F=ma=mxxsqrt((2k)/(m))xx(1)/(2)t^(-1//2)=sqrt((mk)/(2))t^(-1//2).`

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