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4 किग्रा द्रव्यमान का एक पिण्ड सरल आवर्त गति कर रहा है जिसका आयाम 16 सेमी है । जब वस्तु अधिकतम विस्थापन का स्थिति में है तो उस पर लगने वाला बल 12 न्यूटन है । गणना कीजिये -
(ii) 12 सेमी विस्थापन पर त्वरण , स्थितिज ऊर्जा एवं गतिज ऊर्जा

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जब y = 12 सेमी = 0.12 मीटर है
त्वरण `a=omega^(2) y = (5)^(2) xx0.12 =3 " मीटर/ सेकण्ड"^(2)`
स्थितिज ऊर्जा ` U = 1/2 m omega^(2) y^(2) = 1/2 xx 4xx (5)^(2) xx (0.12)^(2)`
= 0.72 जूल
गतिज ऊर्जा ` K = 1/2 momega^(2)(A^(2)-y^(2))`
` = 1/2 xx 4 xx (5)^(2) [ (0.60)^(2) - (0.12)^(2)]`
= 17.28 जूल

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