Question

If the water emerge from an orifice in a tank in which the gauge pressure is `4xx10^(5) Nm^(-2)` before the flow starts, then what will be the velocity of the water emerging out ? Take density of water is `1000 kg m^(-3)`

Answer 1

Here, `p=4xx10^(5) N m^(-2) " and " rho=1000 kg m^(-3), g=10 ms^(-2)`
Apply, `p=h rho g implies h=(p)/(rho g)=(4xx10^(5))/(1000xx10)`
Velocity of efflux, `v=sqrt(2gh)=sqrt((2xx10xx4xx10^(5))/(1000xx10))`
`sqrt(800)=28.28 ms^(-1)`