Question

The level of water in a tank is 5 m high. A hole of area of cross section 1 `cm^(2)` is made at the bottom of the tank. The rate of leakage of water for the hole in `m^(3)s^(-1)` is `(g=10ms^(-2))`
A. `10^(-3) m^(3)s^(-1)`
B. `10^(-4) m^(3)s^(-1)`
C. `10 m^(3)s^(-1)`
D. `10^(-2) m^(3)s^(-1)`

Answer 1

Correct Answer - A
Rate of leakage of water of from the hole
`=Av=Asqrt(2gh)=10^(-4)sqrt(2xx10xx5)=10^(-3)m^(3)s^(-1)`