Question

Calculate the escape velocity from the moon. The mass of the moon `=7.4xx10^22kg` and radius of the moon `=1740km

Answer 1

Correct Answer - A::B::C::D
Escape velocity from the surface of moon is `nu_(e) =sqrt((2GM_(m))/(R_(m))`
Subsituting the values, We have
`nu_(e) =sqrt ((2 xx 6.67 xx 10^(-11) xx 7.4 xx 10 ^(22))/(1.74 xx 10 ^(6)))`
`= 2.4 xx 10^(3) m//s = 2.4 km//s`.