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+1 vote
32.4k views
in Chemistry by (130k points)

What is the quantity of electricity in coulombs needed to reduce 1 mol of  Cr2O72-? Consider the reaction: 

Cr2O72- +14H ++6e --> 2Cr3+ +8H2O

1 Answer

+2 votes
by (93.9k points)
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Best answer

The given reaction is as follows:

CrO72- + 14H+ 6e- → Cr3+ + 8H2

Therefore, to reduce 1 mole of CrO72-, the required quantity of electricity will be:

=6 F

= 6 × 96487 C

= 578922 C

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