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In the figure (i) a thin lens of focal length 10cm is shown. The lens is cut into two equal parts, and the parts are arranged as shown in the figure (ii). An object AB of height 1cm is placed at distance of 7.5cm from the arrangement. The height of the final image will be:
image
A. 0.5 cm
B. 2 cm
C. 1 cm
D. 4 cm

1 Answer

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Best answer
Correct Answer - B
The effective focal length is 5 cm
The height of final image is `=v/uxxO=f/(u+f) xxO =5/(-7.5+5)xx1=2 cm`

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