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A body is vibrating in simple harmonic motion . If its acceleration in `12 cms^(-2)` at a displacement 3 cm from the mean position, then time period is
A. 6.28 s
B. 3.14 s
C. 1.57 s
D. 2.57 s

1 Answer

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Best answer
Correct Answer - B
(b) `|a|=omega^(2)x`
`12omega^(2)(3)`
`therefore omega=2 "rad"s ^(-1)=(2pi)/(T)`
`therefore T=(pi)s " or "3.14 s`

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