Question

A particle is projected horizontally with a speed V=5m/s from the top of a plane inclined at an angle `theta=37^(@)` to the horizontal `(g=10m//s^(2))`

What is the velocity of the particle just before it hits the plane?
A. `5sqrt(3)m//s`
B. `(5)/(2)sqrt(13)m//s`
C. `10sqrt(13)m//s`
D. `5sqrt(26)m//s`

Answer 1

Correct Answer - b
`R=(u cos theta)T+(1)/(2)g sin thetaT^(2)`
`T=(2u sin theta)/(g cos theta)`
`V_(x)= u cos theta+g sin thetaT`