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एक बॉक्स की लम्बाई 24 .0 सेमी , चौड़ाई 18 .6 सेमी तथा ऊँचाई 6 .0 सेमी है बॉक्स के आयतन के आंकलन में हुई अधिकतम प्रतिशत त्रुटि ज्ञात कीजिये ।

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लम्बाई ` L = 24.0 ` सेमी ` Delta L =0.1 ` सेमी
चौड़ाई ` B= 18.6` सेमी ` Delta B=0.1 ` सेमी
ऊंचाई `h = 6.0 ` सेमी ` Delta h = 0.1 ` सेमी
आयतन =लम्बाई `xx` चौड़ाई `xx` ऊंचाई
` V= L. B.h`
आयतन में अधिकतम प्रतिशत त्रुटि
` (Delta V) /(V) xx100 =(Delta L)/( L) xx100 +(Delta B) /(B ) xx100 +(Delta h)/(h)xx100`
`=(0.1 ) /( 24.0) xx100 +(0.1 ) /(18.6)xx100+ (0.1) /( 6.0)xx100=2.6%`

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