Question

If the lines `6x-2=3y+1=2z-2` and `(x-2)/(lamda)=(2y-5)/(-3),z=-2` are perpendicular then `lamda=`
A. 3
B. 2
C. -3
D. 1

Answer 1

Correct Answer - A
The equations of the given lines can be re-written as
`(x-1//3)/1=(y+1//3)/2=(z-1)/3` and `(x-2)/(lamda)=(y-5//2)/(-3//2)=(z+2)/0`
If these lines are perpendicular then
`1xxlamda+2xx(-3/2)+3xx0=0=lamda-3=0implieslamda=3`