Correct Answer - B
The equation of a plane through the line of intersection of the planes.
`x+2y+3z-4=0` and `2x+y-z+5=0` is given by
`(x+2y+3z-4)+lamda(2x+y-z+5)=0`
`impliesx(1+2lamda)+y(2+lamda)+z(3-lamda)-4+5lamda=0` ………………..i
This is perpendicular to the plane `5x+3y+6z+8=0`
`:.5(1+2lamda)+3(2+lamda)+6(3-lamda)=0`
`implies7 lamda+29=0implieslamda=-29//7`
Putting `lamda=-29//7` in i we obtain the equation of the required plane as
`-51x-15y+50z-173=0implies51x+15y-50z+173=0`