Correct Answer - D
The image `(alpha,beta,gamma)` of `(-1,3,4)` in the plane `x-2y+0z=0` is given by
`(alpha+1)/1=(beta-3)/(-2)=(gamma-4)/0=(-2(-1-6+0))/(1+4+0)`
`implies(alpha+1)/1=(beta-3)/(-2)=(gamma-4)/0=14/5impliesalpha=9/4,beta=(-13)/5,gamma=4`
Hence, he image is `(6/5,-13/5,4)`.