Question

EMF of a cell whose half cells are given below is
`Mg^(2+)+2e^(-)toMg(s),E=-2.37V`
`Cu^(2+)+2e^(-)toCu(s),E=+0.33V`

Answer 1

Correct Answer - C
`E_(cell)^(o)=E_("cathode")^(o)-E_("anode"), " "E_(cell)^(o)=0.34-(-2.37)`
`E_(cell)^(o)=2.71V`