Correct Answer - C
`M_("net")=sqrt(M^(2)+M^(2)+2MMcos90^(@))=sqrt(2)M`
(2)
`M_("net")=M-M=0`
(3)
`M_("net")=sqrt(M^(2)+M^(2)+2MMcos30^(@))=Msqrt(2+sqrt(3))`
`M_("net")=sqrt(M^(2)+M^(2)+2MMcos60^(@))=sqrt(3)M`
विन्यास (3) में न्यूटन है अतः अधिकतम होगा।