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एक पतले उत्तल लेन्स तथा एक पतले अवतल लेन्स की क्षमताओं के परिमाण का अनुपात 3/2 है | जब वे सम्पर्क में रखे जाते है, तो इनकी तुल्य फोकस-दूरी 30 सेमी है | इनकी अलग-अलग फोकस-दूरियाँ ज्ञात कीजिए |

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प्रश्नानुशार, `(P_(1))/(P_(2))=(3)/(-2)`
`therefore (f_(1))/(f_(2)) = -(2)/(3)` अथवा `f_(2) = (-3)/(2)f_(1)`
यदि तुल्य फोकस-दूरी `f` हो, तो
`(1)/(f)=(1)/(f_(1))+(1)/(f_(2))=(1)/(f_(1))+(1)/(-(3)/(2)f_(1))=(1)/(f_(1))-(2)/(3f_(1))=(1)/(3f_(1))`
`therefore (1)/(30) = (1)/(3f_(1))` अथवा `f_(1) = 10` सेमी
तथा `f_(2) = -(3)/(2) xx 10 =-15` सेमी |

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