Correct Answer - D
a,b, and c are in A.P. Hence,
2b=a+c
`a/(bc)+2/b=(a+2c)/(bc)ne2/c`
`rArra/(bc),1/c,2/b` are not in A.P.
`(bc)/a+b/2=(2bc+ab)/(2a)nec`
Hence, the given numbers are not in H.P. Again,
`a/(bc)2/b=(2a)/(b^(2)c)ne1/c^(2)`
Therefore, the given numbers are not in G.P.