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30 किलोवोल्ट इलेक्ट्रॉनों के द्वारा उत्पन्न X- किरणों की (a ) उच्चतम आवृत्ति तथा ( b) निम्नतम तरंगदैर्घ्य प्राप्त कीजिए ।

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X-किरण नलिका में इलेक्ट्रॉनों का त्वरक विभव
`V=30` किलोवोल्ट `=3xx10^(4)` वोल्ट
इलेक्ट्रॉन की ऊर्जा `E=eV=(1.6xx10^(-19))xx3xx10^(4)`
`=4.8xx10^(-15)` जूल|
यही X-किरणों की अधिकतम ऊर्जा होगी
`:. E_("max")=hv_("max")=4.8xx10^(-15)` जूल
(a) उच्चतम आवृत्ति , `v_(max")=(4.8xx10^(-15)J)/(6.63xx10^(-34)J-s)`
`=7.24xx10^(18)s^(-1)`
`=7.24xx10^(18)` हर्ट्स ।
(b) निम्नतम तरंगदैर्घ्य, `lambda_("min")=(c)/(v_("max"))=(3.0xx10^(8))/(7.24xx10^(18))`
`=0.041xx10^(-9)` मीटर
= 0.041 नैनोमीटर ।

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