Correct Answer - C::D
When ` theta = 0^(@), the charged particle is projected along ` x - axis` , due to `vec(B)` the charged particle will tend to move in a circular path in ` y -z `plane but due to force of electric field , the particle will move in a helical path with increasing pitch. Therfore options `(A) and (B)` are incorrect.
When ` theta = 10^(@)`, we can resolve velocity into two rectangular components. One al,ong ` x- axis(v cos 10^(@))` and one along ` y - axis (v sin 10^(@))`. Due to ` v cos 10@` , the particle will move in circular path and due to ` v sin 10^(@)` plus the force due to electric field, the particle will undergo helical motion with its pitch increasing.
If ` theta = 90^(@)`, the charge is moving along the magnetic field. Therefore the force due to magnetic field is zero . But the force due to electric field will accelerate the particle along ` y - axis`.