Question

A conductor (shown in the figure) carrying constant current `I` is kept in the `x-y` plane in a uniform magnetic field ` vec(B)`. If ` vec(F)` is the magnitude of the total magnetic force acting on the conductor, then the correct statement(s) is (are)

A. If `vec(B)` is along `hat (z)` , `F prop (L+R)`
B. If `vec(B)` is along `hat (x)` ,F = 0`
C. If `vec(B)` is along `hat (y)` , `F prop (L+R)`
D. If `vec(B)` is along `hat (z)` , `F = 0`

Answer 1

Correct Answer - A::B::C
` vec(F) = I [(int vec( dl ))xx vec(B)]`
If ` vec(B)` is along `z` then ` vec(F)` = I[(2L+ 2R)hat(i) xxB hat (x)]`
option ` [A]` is correct
If ` vec(B)` is along ` vec(x)` then `vec(F) = I[(2L+ 2R)hat(i) xxB hat (i)] = 0`
If `vec(B)` is along ` vec(y)` then ` vec(F) = I[(2L+ 2R)hat(i) xx hat (j)]`
Option `(b) and (c)` are also correct