Question

Figure shows two capacitors `C_1 and C_2` connected with 10 V battery and terminal A and B are earthed. The graphs shows the variation of potential as one moves from left to right. Then the ratio `C_1//C_2` is

A. `5//2`
B. `2//3`
C. `2//5`
D. `4//3`

Answer 1

Correct Answer - B
Potential drops across `C_(1)` and `C_(2)` are `6V` and `4V`, repectively. Since they are in series, same charge flows through them and
`(C_(1))/(C_(2))=(V_(2))/(v_(1))=(2)/(3)`