Correct Answer - a.
For a concave mirro,
`u=-(15)/(2)cm, v=?`
`f=(10)/(2)cm=-5cm`
`(1)/(v)=(1)/(f)-(1)/(u)-(1)/(-5)-(1)/(-15//2)`
`=(1)/(5)+(2)/(15)=(-1)/(15)`
or `v=-15cm`
Clearly, the position of the final image is on the pole of the convex mirror.