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A positively charged ball hang a silk thread. We put a positive test charge `q_(0)` at a point and measure `F//q_(0)`, then it can be predicted that the electric field strength `E`.
A. `gt F//q_(0)`
B. `=F//q_(0)`
C. ` lt F//q_(0)`
D. Can not be estimated

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Correct Answer - a
Because of the presence of positive test charge `q_(0)` in front of positively charged ball, charge on the ball will be redistributed, less charge on the front half surface and more charge on the back half surface. As a result of this net force `F` between ball and point charge will decrease i.e., actual electric field will be greater than `F//q_(0)`

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