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A radioactive nucleus undergoes a series of decay according to the scheme
`A overset(alpha)rarr A_(1) overset(beta^(-))rarr A_(2) overset(alpha)rarr A_(3)^(172) overset(gamma)rarr A_4`.
A. 172 and 60
B. 174 and 70
C. 176 and 69
D. 176 and 70

1 Answer

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Best answer
Correct Answer - A
(a) Two `alpha-`particle reduce mass number by `8`.
`:.` New mass number `= 180 - 8 = 172`
Emission of two `alpha-`particle reduces charge number by `4`. Emission of `beta` particles increases charge number by `1`.
`:.` New charge number `= 72 - 4 + 1 = 69`.

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