Question

A circular brass loop of radius a and resistance R is placed with it plane perpendicular to a magnetic field, which varies with time as `B = B_(0) sin omega t`. Obtain the expression for the induced current in the loop.

Answer 1

Induced current,
`I = (I n d u c e d e.m.f.)/(resistance) (e) /(R )`
` = - (d phi // dt)/(R ) = (-1)/(R ) (d)/(dt) (BA cos 0^(@))`
`I = - (A)/(R ) (d)/(dt) (B_(0) sin omega t) = - (AB_(0))/(R ) cos omega t (omega)`
`= -(A omega B_(0))/(R )`