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Two resistors of `10 Omega` and `20 Omega` and an ideal inductor of `10 H` are connected to a `2 V` battery as shows in Fig. key `K` is inserted at time `t = 0`. The initial `(t = 0)` and final `(t rarr oo)` currents through the battery are
image

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Correct Answer - `1/15A, 1/10A`
at `t=0` inductor acts as open circuit.
`i_(t=0)=2/30=1/15 amp`.
at `t=oo` inductor acts as short circuit.
`i_(t=oo)=2/20=1/10 amp`

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