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In the Cannizzaro reaction given below:
`2Ph-CHO overset(overset(Θ)OH)rarrPh-CH_(2)OH+PhCO_(2)^(-)` the slowest step is:
A. the attack of `.^(-) OH` at the carbonyl group.
B. the transfer of hydride to the carbonyl group.
C. the abstraction of proton from the carboxylic acid.
D. the deprotonation of `Ph CH_(2) OH`.

1 Answer

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Best answer
Correct Answer - B
The possible mechanism is
The showest stop is the transfer of hydride to the carbonyl ground as shown in stop (ii).
image

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