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नीचे कुछ अर्द्ध-सेल अभिक्रियाऐं दी गई है के लिए होगा
A. `-2.69V,` अभिक्रिया नहीं होगी
B. `-2.69V,` अभिक्रिया होगी
C. `-0.33V,` अभिक्रिया नहीं होगी
D. `-0.33V,` अभिक्रिया होगी

1 Answer

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Best answer
`becauseDeltaG^(@)=-nFE^(@)`
`Mn^(2+)+2e^(-)toMn,E^(@)=-1.18V`
`:.DetaG_(1)^(@)=-2F(-1.18)=2.36F`
`Mn^(3+)+etoMn^(2+),E^(@)=+1.51V`
`:.DeltaG_(2)^(@)=-F(1.51)=-1.51`
`3Mn^(2+)toMn+2Mn^(3+)`
`DeltaG_(3)^(@)=DeltaG_(1)^(@)-2Delta_(2)^(@)`
`=2.36F-2(-1.51)F`
`=(2.36+3.02)F=5.38F`
परन्तु `DeltaG_(3)^(@)=-2FE^(@)`
`5.38F=-2FE^(@)`
या `E^(@)=-2.69V`
`E^(@)` का मान ऋणात्मक है अतः अभिक्रिया अस्वतः होगी

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