(i) परिपथ में,
प्रतिरोध R = 10 ओम
प्रेरण प्रतिघात `X_(L) = omegaL = 2pif L = 2 pi (50)((1)/(10pi))`
` = 10` ओम
`therefore` प्रतिबाधा `Z = sqrt(R^(2) + X_(L)^(2)) = sqrt((10)^(2) + (10)^(2))`
` = 10sqrt(2)` ओम
धारा `L_(rms) = (V_(rms))/(Z) = (200)/(10sqrt(2)) = (20)/(sqrt(2))`
`= 10sqrt(2)` ऐम्पियर
शक्ति गुणांक `cos phi = (R )/(Z) = (10)/(10sqrt(2)) = (1)/(sqrt(2))`
`therefore` परिपथ में औसत शक्ति क्षय
`barP = V_(rms) xx L_(rms) xx cos phi`
`= 200 xx 10sqrt(2) xx (1)/(sqrt(2))`
` = 2000` वाट
(ii) `because " " cos phi = (1)/(sqrt(2)) = cos 45^(@)`
`therefore " " phi = 45^(@)`
