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एक p - n सन्धि डायोड का अग्र अभिनति में प्रतिरोध 20 ओम है। यदि अग्र वोल्टेज में 0.025 वोल्ट का परिवर्तन हो तो डायोड धारा में कितना परिवर्तन होगा ?

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यदि सन्धि पर अग्र अभिनत वोल्टेज में परिवर्तन `Delta V ` तथा डायोड धारा में परिवर्तन `Delta I ` हो तो सन्धि डायोड का अग्र प्रतिरोध
`r=(Delta V)/(Delta I)`
`therefore Delta I = (Delta V)/(r)=(0.025" वोल्ट")/(20" ओम") `
`=1.25 xx10^(-3)A` अथवा 1.25 mA

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