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यदि किसी प्याले में 0.25 kg पानी रखा हो, तो उसमें इलेक्ट्रॉन तथा प्रोटॉनों की कुल संख्या ज्ञात करे | इनके आवेश कुलाम (C ) में व्यक्त करे |

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Correct Answer - `8.36xx10^(24), 1.34xx10^(7)C`
पानी का अणु-द्रव्यमान (molar mass) = 18g, जिसमें अणुओ की संख्या `N_(A)=6.02xx10^(23)` है |
`therefore" "0.25 kg` में पानी के अणुओ की संख्या `=(6.02xx10^(23)xx250 g)/((18g))=83.6xx10^(23)`,
चूँकि प्रत्येक `H_(2)O` अणु में 10 इलेक्ट्रॉन तथा 10 प्रोटॉन है | अतः इलेक्ट्रॉन तथा प्रोटॉन की कुल संख्या `=83.6xx10^(24)`, तथा इनका आवेश `Q="ne"=(83.6xx10^(24)xx1.6xx10^(-19)) C=1.34xx10^(7)C.`

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