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एक निकट दृष्टि वाला व्यक्ति 1.5 cm दूरी तक की वस्तुओं को साफ-साफ देख सकता है | इस दोष के उपचार के लिए आवश्यक चश्मे की क्षमता निकाले |

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माना लिया कि आवयश्क चश्मे के लेंस की फोकस-दूरी f है,
तो सूत्र `(1)/(v)-(1)/(u)=(1)/(f)` यहाँ `v = -1.5 m, u = -oo.`
`therefore (1)/(-1.5)-(1)/(-oo) = (1)/(f)` या `(1)/(f)=-(1)/(15)`
`therefore f = -1.5 m`
यहाँ ऋणात्मक चिन्ह से यह स्पष्ट है कि लेंस अवतल (concave) होना चाहिए |
यदि लेंस की क्षमता P हो , तो
`P = (1)/(f) =(1)/(-1.5) =-0.67` डायोप्टर
अतः, दोष के उपचार के लिए `-0.67 D` के अवतल लेंस की आवश्यकता होगी |

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