Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
80 views
in Chemistry by (60.3k points)
closed by
In accordance to Arrhenius equation, the plot of log k against `(1)/(T)` is a straight line. The slope of the line is equal to
A. `(-E_(a))/(R )`
B. `(-2.303)/(E_(a).R)`
C. `(-E_(a))/(2.303R)`
D. `(-E_(a))/(2.303)`

1 Answer

0 votes
by (66.4k points)
selected by
 
Best answer
Correct Answer - C
Arrhenius equation can be written as
`logk=logA-(E_(a))/(2.303R)`,
On comparing this equation with the straight line equation,
`y=mx+c`
we get,, `y=logk, m=-(E_(a))/(2.303R),x=(1)/(T),C=logA`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...