Question

For the first order reaction, `k=5.48 xx 10^(-4)s^(-1)`, the two-third life time for this reaction is
A. 2005 s
B. 1000 s
C. 2000 s
D. 3005 s

Answer 1

Correct Answer - A
For first order reaction, we know that
`k=(2.303)/(t).log.(a)/((a-x))`
Hence, `t=(2.303)/(5.48 xx 10^(-4))xxlog .(a)/(a-(2)/(3)a)`
`=(2.303xx10^(4))/(5.48)xxlog3`
`=(2.303xx10^(4))/(5.48)xx0.4771=2005s`