Correct Answer - B
Since 1 radian ` = (7pi)/(22)`
`therefore` 12 radian
` =(7pi)/(22) xx 14 = (49pi)/(11) = 4pi - (2pi)/(1)` and 14 radian
` = (7pi)/(22) xx 14 = (49pi)/(11) = 4pi + (5pi)/(11)`
`therefore cos^(-1)(cos 12) - sin^(-1) (sin 14)`
` = cos^(-1) cos (4pi - (2pi)/(11))`
`-sin^(-1)[sin(4pi +(5pi)/(11))]`
`=cos^(-1) cos ((2pi)/(11)) - sin^(-1)(sin.(5pi)/(11))`
` = 4pi - 12 - (14 - 4pi) = 8pi - 26`
