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20 सेमी फोकस-दूरी का उत्तल लेंस एक 25 सेमी फोकस-दूरी के अवतल लेंस के सम्पर्क में है। संयुक्त लेंस की फोकस-दूरी एवं क्षमता ज्ञात कीजिए।

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सूत्र - `1/f=1/(f_1)+1/f_2`
दिया है - `f_1 = 20 ` सेमी , `f_2`=-25 सेमी
सूत्र में मान रखने पर , `1/f=1/20+1/(-25)=1/20-1/25=(5-4)/100=1/100`
`therefore ` f=100 सेमी = 1 मीटर तथा क्षमता `P=1/f=1/1=1` डाइऑप्टर

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