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सोडियम के स्पेक्ट्रमी उत्सर्जन रेखा के प्रकाश का तरंगदैघ्र्य 589 nm है | वह गतिज ऊर्जा ज्ञात कीजिय जिस पर एक न्यूट्रॉन का डी-ब्रॉगली तरंगदैघ्र्य समान होगा |

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दिया है --- `lamda = 589 nm = 589 xx 10^(-9)m`
`lamda = h/sqrt(2mk)`
या `lamda^2 = h^2/(2mk)`
या `k = h^2/ (2n lamda^2), ` ( जहां k गतिज ऊर्जा )
न्यूनताओं की गतिज ऊर्जा
`K_n =((6*6 xx 10^(-34))^2)/(2xx1*67 xx10^(-27)xx(589x10^(-9))^2)`
` = 3*75 xx 10^(-28) J`
` = (34*75 xx 10^(-28))/(1*6 xx 10^(-19))eV`
`= 2*34 xx 10^(-9) eV`

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