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विशुद्ध `""_(6)^(11)C` के 2.2 मिलीग्राम रेडियो - एक्टिव नमूने की अर्द्धआयु 1224 सेकण्ड है | अग्र की गणना कीजिए -
सक्रियता जबकि नमूने का `5mu g` शेष है |

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दिया है - रेडियोएक्टिव नमूने का द्रव्यमान
= 2.2 मिलीग्राम `=2.2xx10^(-3)` ग्राम
`T_(1//2)=1224` सेकण्ड
`5mu g=5xx10^(-6)` ग्राम में परमाणुओं की संख्या
`=(6.025xx10^(23)xx5xx10^(-6))/(11)=2.74xx10^(17)`
`lambda=(0.6931)/(T_(1//2))=(0.6931)/(1224)=0.00057`
`=5.7xx10^(-4)("सेकण्ड")^(-1)`
सक्रियता
`R=lambda"N"=5.7xx10^(-4)xx2.74xx10^(17)`
`=15.618xx10^(13)=1.56xx10^(14)` बैकेरल |

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