प्रश्नानुसार,
`T_(1) = 350 K, T_(2) = 400 K, k_(2)= 5 xx k_(1)` तथा `R=8.314 JK^(-1) mol^(-1)`
आरहीनियम समीकरण में मान रखने पर,
`log_(10)(5 x k_(1))/k_(1) = E_(a)/(2.303 xx 8.314) [1/350 -1/400]`
`0.6990 = E_(a)/19.147 xx 50/(350 xx 400)`
`E_(a)=(0.6990 xx 19.147 xx 350 xx 400)/(50) = 37474.5 J "mol"^(-1)`
`E_(a) = 37.47 kJ mol^(-1)`