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एक प्रथम कोटि अभिक्रिया के लिए वेग सिथरांक `60s^(-1)` हैं। अभिक्रिया के प्रारम्भिक सांद्रण का `1//16` भाग शेष रहने तक अभिक्रिया में कितना समय लगेगा ?

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`t=(2.303)/(k) log_(10)([A]_(0))([A])`
`=(2.303)/60 log_(10) ([A]_(0))/(1/16 xx [A]_(0))`
`=4.6 xx 10^(-2)s`

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