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A circular current loop of magnetic moment `M` is in an arbitrary orientation in an external magnetic field `vec(B)`. The work done to rotate the loop by `30^(@)` about an axis perpendicular to its plane is `:`
A. `MB`
B. `sqrt(3)(MB)/(2)`
C. `(MB)/(2)`
D. zero.

1 Answer

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by (91.3k points)
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Best answer
Correct Answer - D
Rotation of loop by `30^(@)` about an axis perpendicular to its plane does not change the angle between magnetic moment and magnetic field. Hence, no work is done.

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