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At what temperature, `DeltaG` of a reaction is equal to `-5.2 kJ mol^(-1)` ? `DeltaH` and `DeltaS` of the reaction are respectively `145.6 kJ mol^(-1)` and `116 JK^(-1)`.
A. `1300^(@)C`
B. `130 K`
C. `1300 K`
D. `130^(@)C`

1 Answer

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Best answer
Correct Answer - C
`DeltaG=DeltaH-TDeltaS`
or `T=(DeltaH-DeltaG)/(DeltaS)=(145600(J)-5200(J))/(116(J))`
`=(150800)/(116)=1300K`

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