Question

Given standard electrode potentials
`K^(o+)|K=-2.93V, Ag^(o+)|Ag=0.80V`,
`Hg^(2+)|Hg=0.79V`
`Mg^(2+)|Mg=-2.37V,Cr^(3)|Cr=-0.74V`
Arrange these metals in their increasing order of reducing power.

Answer 1

It may be noted that lesser the `E^(@)` value for an electrode, more will be reducing power. The increasing order of reducing power is :
`Ag^(+)//Ag lt H^(2+)//Hg lt Cr^(3+)//Cr lt Mg^(2+)//Mg lt K^(+)//K`