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Which of the following combination will produce `H_(2)` gas ?
A. Fe metal and Conc. `HNO_(3)`
B. Cal metal and Conc. `HNO_(3)`
C. Au metal and NaCN(aq) in the presence of air
D. Zn metal and NaOH(aq)

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Correct Answer - D
(d) It is the correct answer.
`Zn+2NaOHrarrNa_(2)ZnO_(2)+H_(2)`
Fe becomes passive with conc. `HNO_(3)`
Cu liberates `NO_(2)` gas with conc. `HNO_(3)`
Gold forms a soluble complex with NaCl in the presence of air.

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