Question

Position of a particle moving along x-axis is given by `x=2+8t-4t^(2)`. The distance travelled by the particle from `t=0` to `t=2` is:-

Answer 1

Correct Answer - B
Area of (v-t) curve=displacement
`x=2+8t-4t^(2)`
`v=(dx)/(dt)=8-8t`
`(v)/(t),(8)/(0),(0)/(1),(-8)/(2)`
`v=(dx)/(dt)=8-8t`

Distance travelled from t=0 to t=2 sec
`=(1)/(2)xx1xx8+(1)/(2)xx1xx8=4+4=8m`